Asked the AI robot ChatGPT this question today:
Write a program in z80 assembler that stops the interrupts, multiplies the value in the accumulator by 2 and then starts the interrupts again
It replied
di ; disable interrupts
ld a, (ix+0) ; load value from memory into the accumulator
add a, a ; multiply the accumulator by 2
ld (ix+0), a ; store the result back in memory
ei ; enable interrupts
ret ; return from subroutine
Any thoughts about this?
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